Translation

Date in de|es|fr|it|nl
Type:	code fragment
Added by:	narcisse
Entered:	12/03/2004
Last modified:	03/12/2003
Rating:	- (fewer than 3 votes)
Views:	3932
Function that display date for 5 contry
<?php
function dateLang($phpLang="en"){

                              switch($phpLang){

                                case "de":

                                  $strDay   = array(0 => "Sonntag","Montag","Dienstag","Mittwoch","Donnerstag","Freitag","Sonnabend");

                                  $strMonth = array(1 => "Januar","Februar","M&auml;rz","April","Mai","Juni","Juli","August","September","Oktober","November","Dezember");

                                  $intDay   = " ".date("j").". ";

                                  $intYear  = " ".date("Y");

                                  return $strDay[date("w")].$intDay.$strMonth[date("n")].$intYear;

                            

                                case "es":

                                  $strDay   = array(0 => "Domingo","Lunes","Martes","Mi&eacute;rcoles","Jueves","Viernes","S&aacute;bado","Enero");

                                  $strMonth = array(1 => "febrero","marzo","abril","mayo","junio","julio","agosto","septiembre","octubre","noviembre","diciembre");

                                  $intDay   = " ".date("j")." de ";

                                  $intYear  = " ".date("Y");

                                  return $strDay[date("w")].$intDay.$strMonth[date("n")].$intYear;

                            

                                case "fr":

                                  $strDay   = array(0 => "Dimanche","Lundi","Mardi","Mercredi","Jeudi","Vendredi","Samedi");

                                  $strMonth = array(1 => "janvier","f&eacute;vrier","mars","avril","mai","juin","juillet","ao&ucirc;t","septembre","octobre","novembre","d&eacute;cembre");

                                  $intDay   = strtr( " ".date("j")." ", array(" 1 " => " 1er ") );

                                  $intYear  = " ".date("Y");

                                  return $strDay[date("w")].$intDay.$strMonth[date("n")].$intYear;

                            

                                case "it":

                                  $strDay   = array(0 => "domenica","luned&igrave;","marted&igrave;","mercoled&igrave;","gioved&igrave;","venerd&igrave;","sabato");

                                  $strMonth = array(1 => "gennaio","febbraio","marzo","aprile","maggio","giugno","luglio","agosto","settembre","ottobre","novembre","dicembre");

                                  $intDay   = " ".date("j")." ";

                                  $intYear  = " ".date("Y");

                                  return $strDay[date("w")].$intDay.$strMonth[date("n")].$intYear;

                            

                                case "nl":

                                  $strDay   = array(0 => "zondag","maandag","dinsdag","woensdag","donderdag","vrijdag","zaterdag");

                                  $strMonth = array(1 => "januari","februari","maart","april","mei","juni","juli","augustus","september","oktober","november","december");

                                  $intDay   = " ".date("j")." ";

                                  $intYear  = " ".date("Y");

                                  return $strDay[date("w")].$intDay.$strMonth[date("n")].$intYear;

                            

                                default:

                                  $strDay   = array(0 => "Sunday, ","Monday, ","Tuesday, ","Wednesday, ","Thursday, ","Friday, ","Saturday, ");

                                  $strMonth = array(1 => "January","February","March","April","May","June","July","August","September","October","November","December");

                                  $intDay   = strtr( date("j")."th,", array("1th"=>"1st", "2th"=>"2nd", "3th"=>"3rd", "21th"=>"21st", "22th"=>"22nd", "23th"=>"23rd", "31th"=>"31st") );

                                  $intYear  = " ".date("Y");

                                  return $strDay[date("w")].$strMonth[date("n")].$intDay.$intYear;

                              }

                            }
?>
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